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x^2+2x+72=-25x
We move all terms to the left:
x^2+2x+72-(-25x)=0
We get rid of parentheses
x^2+2x+25x+72=0
We add all the numbers together, and all the variables
x^2+27x+72=0
a = 1; b = 27; c = +72;
Δ = b2-4ac
Δ = 272-4·1·72
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-21}{2*1}=\frac{-48}{2} =-24 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+21}{2*1}=\frac{-6}{2} =-3 $
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